00:02
Hi friends, here it is given a force f is equal to 2x cross square of y, i cap, minus x square plus 1, sine of 2 by j cap.
00:25
First part, taking the curl of the force, it is i cap, j cap, k cap, dale over dix, dale, y, dail over dail, y, dail over dail j, dail over dill j, z.
00:44
2x cost square of y minus x square plus 1 sine of 2 y and 0 solving it you find it to be 0 so force is conservative second part we have to calculate the work done work done is f dot dr that is 2x cos square by d x x plus plus minus x square plus 1 sine of 2 by divide for the path 0 0x by z first from 002 x 0 0 0 0 0 0 0 0 0 0 0 0 is called to d y upon d z to be zero so w one you will get integration from zero to x to x cost squared 0 d x so it is to be x squared now second from x zero zero to zero z so w two so here y is zero d x is called to d x is called to d is equal to 0.
03:01
So w2, 0, 0, d, that is 0.
03:07
3rd, from x 0, x, 2, x by j, so d x is equal to dz.
03:23
So, d x is called to dz is called to 0.
03:38
Here, d x is called to d .y is called to 0...