00:01
We wish to show that the mean value theorem applies, and then we'll determine where it applies for this function.
00:06
The function itself is continuous between 0 and 1, including the endpoints.
00:14
Reason for this is that unless x squared is greater than 1, we can take the function value.
00:23
And all x values between 0 and 1, including 0 and 1, do give us the function value as being.
00:31
Less than 1.
00:34
X square being less than 1.
00:35
The derivative of the function using the chain rule, remember that the square root to half power, is 1ā2x squared to the negative 1ā2x, times negative 2x, which reduces to x over 2 square root 1 minus x square.
00:59
By rule, if the mean value theorem applies, and first of all, this is a differentiable function on the interval, open interval, zero to one.
01:15
The bottom is zero at the x value of one, but again, it just has to be on the open interval from zero to one.
01:22
And every x value we fill in between zero and one will give us a real answer.
01:27
Mean value theorem says that f prime of c will equal f of b minus f of a over b minus a at some c value...