Question
Verify that $\mathbf{E}$ and $\mathbf{B}$ in (6.55) are unchanged by the gauge transformation$$A_{\mu} \rightarrow A_{\mu}^{\prime}=A_{\mu}+\partial_{\mu} \chi$$where $\chi$ can be any function of $x$. Use this freedom to write Maxwell's equations in the form$$\square^{2} A^{\mu}=j^{\mu} \quad \text { with } \partial_{\mu} A^{\mu}=0 .$$
Step 1
The electric field is given by: \[ \mathbf{E} = -\nabla \phi - \frac{\partial \mathbf{A}}{\partial t} \] and the magnetic field is given by: \[ \mathbf{B} = \nabla \times \mathbf{A} \] where \(A_{\mu} = (\phi, \mathbf{A})\). Show more…
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