00:01
Hi guys in this problem we are given that x follows e gama distribution with parameter alpha and lambda so we know that f of x is equal to lambda power a over gamma of alpha or lambda power alpha over gamma of alpha times x power alpha times e or negative lambda x this is for x more than or equal to zero so let's find the mean of x we know that the mean of x, it's just integration from 0 to infinity for x times f of x, which is lambda power alpha over gamma of alpha times x power alpha minus 1 times e4 negative lambda x d x.
00:49
Okay, so this is equal to gamma of alpha plus 1 over lambda times gamma of alpha times integration from 0 to infinity for lambda.
01:02
Our alpha plus 1 over gamma of alpha plus 1 times x power alpha plus 1 minus 1 times e .0.
01:15
Negative lambda x d x.
01:19
So in this case we have gamma of alpha plus 1 over lambda times gamma of alpha times 1.
01:35
Times alpha minus 1 factory, which is alpha over lambda.
01:43
Okay, then we need to find the mean of alpha square, sorry, the mean of x squared.
01:52
So it's the same way, it's integration from 0 to infinity for x squared times f of x, which is lambda power alpha over gamma of alpha times x power alpha minus 1 times e per negative lambda x, d x.
02:12
Okay, so in this case it's integration...