Verify that the function $f^{-1}(x)$ is the inverse of $f(x)$ by showing that $f\left(f^{-1}(x)\right)=x$ and $f^{-1}(f(x))=x .$ Graph $f(x)$ and $f^{-1}(x)$ on the same axes to show the symmetry about the line $y=x$.
$$f(x)=\frac{1}{x} ; f^{-1}(x)=\frac{1}{x}, x \neq 0$$