00:01
We're asked to verify that this is a pdf over this interval, and then find the probability that the random variable is between 2 and 15.
00:10
So to check it's a pdf, it needs to be positive on the interval, which is good here.
00:17
It needs to be continuous.
00:18
This is continuous.
00:19
It's a ratio of two continuous functions.
00:22
The denominator isn't zero.
00:25
And so the last thing we need to check is that it integrates to 1 over this interval.
00:31
So let's check that.
00:35
So we have an improper integral here.
00:41
And so to evaluate this, i think the easiest way is if we use an integration by parts, we can get rid of this natural log.
00:51
So if i let that be u, then du becomes 1 over x, dx.
00:55
Dv has to be whatever is left over.
00:59
So that's 1 over x squared, and the antiderivative of that is 1 over x.
01:04
So what does this evaluate to? we have uv, where evaluating it between 1 and infinity, then we have plus minus the integral of v, du, which works out to be plus integral from 1 to infinity of 1 over x squared dx.
01:34
Okay, and so let's evaluate this.
01:39
Rather, before evaluating the limits, let's just find the, anti -derivative.
01:45
So i'll drop the limits for a second...