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Problem number 9.
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To verify stokes theorem in the given case, we will have to show that for the surface s, its boundary, the closed curve c and the vector f and the vector field f, the line and the surface integral are equal.
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In other words, we can say that the line integral of f of dx equals the surface integral of the curl of the vector field f and d .s.
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In order to evaluate the circulation integral, we first need to compute f .r dash of t.
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The curve c is the circle x squared plus y squared equals 16 minus 7, which is equal to 9.
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With a counterclockwise orientation, we switch to the polar coordinates, x equals 3 cosine t and y equals 3 sine t.
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And the parameterization is r of t which is equal to 3 cosine t 3 and 0 4 bigger than or equal 0 and less than or equal to pi r dash of t equals negative 3 sine t 3 cosine and 0 okay the field vector important coordinate is f equals y minus z z minus x and x minus y f of t equals 3 sine t negative 3 cosine t and 3 cosine t minus 3 sine t f dot r dash of t equals this equation multiply negative 3, sine t, 3 cosine t and 0, which is equal to negative 9, sine t squared, minus 9 cosine t squared, which is equal to negative 9...