We substitute x=4 and y=3 into both equations.
For the first equation, we have:
\[2x^2 = 2(4)^2 = 32\]
\[3y + 23 = 3(3) + 23 = 32\]
Since both sides of the equation are equal, the point (4,3) satisfies the first equation.
For the second equation, we have:
\[y =
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