Question
Verify that $y=-t \cos t-t$ is a solution of the initial-value problem$$t \frac{d y}{d t}=y+t^2 \sin t \quad y(\pi)=0$$
Step 1
Step 1: To verify that $y = -t\cos t - t$ is a solution of the given initial-value problem, we need to check two things: Show more…
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Verify that $y=-t \cos t-t$ is a solution of the initial- value problem $$ t \frac{d y}{d t}=y+t^{2} \sin t \quad y(\pi)=0 $$
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Verify that $y=-t \cos t-t$ is a solution of the initial-value problem $$t \frac{d y}{d t}=y+t^{2} \sin t \quad y(\pi)=0$$
$\begin{array}{c}{\text { Verify that } y=-t \cos t-t \text { is a solution of the initial-value }} \\ {\text { problem }} \\ {t \frac{d y}{d t}=y+t^{2} \sin t \quad y(\pi)=0}\end{array}$
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