00:01
All right, to verify this identity, i obviously see that the left side is more complicated, so i'm going to be working with that side, and i'm going to distribute this cosine to both terms.
00:12
So i'm going to write cosine of x times secant of x, and cosine times negative cosine will be negative cosine squared of x, and i'm just not going to even do anything with the right side.
00:23
I'm just to leave it alone.
00:24
I can only work with one side at a time anyway.
00:26
So what i also see over here is cosine and sikin are actually reciprocals of each other.
00:33
So i have a couple choices.
00:34
I can rewrite this as 1 over secant of x times secant of x over 1, where i did really nothing to the secon of x and i see that that cancels, reciprocal multiplied together equals 1.
00:47
Or i can rewrite this as cosine of x times 1 over cosine of x using the reciprocal identity of secant...