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Hello.
00:01
So here we are supposing that f prime is integral, integrable, and we have that the absolute value of f prime of x is less than or equal to m for all x.
00:14
And we want to prove that the absolute value of f of x is less than or equal to the absolute value of f of a plus m times the absolute value of x minus a for every a.
00:27
Okay.
00:28
So we are going to prove this by contrast.
00:30
Let's assume that f is a continuous function and differentiable and that there does exist some m such that the absolute value of f prime of x is going to be less than or equal to m.
00:49
Then let's assume there are two numbers a and b such that the absolute value of f of a is going to be greater than.
01:00
The absolute value of f of b plus m times the absolute value of a minus b.
01:09
Okay, then we just can solve this for m, and we get that the absolute value of f of a minus the absolute value of f of b divided by the absolute value of a minus b is going to be greater than m.
01:32
So let's call, let's call it back here.
01:35
Let's call this first equation, equation one...