00:01
Okay, i want to prove this by induction and i want n to take values which are natural numbers.
00:09
Or the first natural number is 1.
00:12
So we'll test for n equals 1 and see if it works.
00:18
So test for n equals 1.
00:22
That's the first step.
00:24
The left hand side, if n is 1, then we simply have 5 negative 8, 2.
00:35
Minus 3 as the matrix power 1 could be here but not required.
00:45
In the right hand side replace the n by 1 i will get 4 plus 1 is the first top left then negative 8 and 2n is clearly 2 and then 1 minus 4 n is 1 minus 4 and that is the same thing you get 5 negative 8, 2 negative 3 and that equals the left -hand side.
01:30
Hence expression is true for n equals 1.
01:45
Okay next test for n equals k.
01:57
Sorry, that should be assumed true for n equals k.
02:01
So we'll change that and put assume true for n equals k.
02:01
So we'll change that and put assume true for n equals k.
02:15
Other words this we assume is true.
02:20
Just replace the n here by k on both sides.
02:28
Then if this is true then so is the following.
02:44
The same thing as before and we post multiply on both sides by 5 minus 8 to minus 3.
02:55
In other words a valid algebraic operation on both sides.
03:00
Same thing on both sides.
03:02
So if this is true, so is all of this.
03:08
The keyword here is of course if...