Question
Verify the formulas by differentiation.$$\int \frac{1}{(x+1)^{2}} d x=-\frac{1}{x+1}+C$$
Step 1
We can rewrite $\frac{1}{x+1}$ as $(x+1)^{-1}$ and the constant $C$ remains the same. So, we have $(x+1)^{-1} + C$. Show more…
Show all steps
Your feedback will help us improve your experience
Bobby Barnes and 94 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Verify the formulas by differentiation. $$\int \frac{1}{(x+1)^{2}} d x=\frac{x}{x+1}+C$$
Applications of Derivatives
Antiderivatives
Verify the formulas by differentiation. $$\int \frac{1}{x+1} d x=\ln |x+1|+C, \quad x \neq-1$$
Verify the formulas by differentiation. $$\int \frac{d x}{a^{2}+x^{2}}=\frac{1}{a} \tan ^{-1}\left(\frac{x}{a}\right)+C$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD