00:01
Alright, we're basically trying to solve this.
00:03
Coatangent x over secant x.
00:05
Now, i'm going to write down some notes, and it's something that it's imperative that you learn this.
00:12
I shouldn't say learn this, but keep this in mind, all these fundamental trig identities.
00:17
Coatangent of x is equal to cosine of x over sine of x.
00:23
I remember secant and cosine are reciprocals of one another.
00:34
And also remember, sine squared plus cosine squared is equal to 1.
00:43
1, 2, 3, 4.
00:45
These 4 are a necessity for this problem.
00:49
All right, cotangent is cosine of x divided by sine of x.
00:55
And secant of x is, we're going to keep it as it is for now.
01:00
But you know it's 1 over cosine of x.
01:02
It will be important later.
01:03
This is cosine of x over sine of x, and we're essentially multiplying it by 1 over secant of x.
01:13
Multiplying by 1 over seant of x, this is the same thing as dividing by secant of x.
01:18
So this and this are basically the same thing.
01:24
So i'm going to move on...