Question
Verify the identity.$$\frac{\tan v-\cot v}{\tan ^{2} v-\cot ^{2} v}=\sin v \cos v$$
Step 1
Step 1: First, we rewrite the given expression using the identity $a^2 - b^2 = (a - b)(a + b)$: $$ \frac{\tan v-\cot v}{\tan ^{2} v-\cot ^{2} v} = \frac{\tan v-\cot v}{(\tan v - \cot v)(\tan v + \cot v)} $$ Show more…
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