00:05
For part a of the given problem, we need to find the derivative first.
00:10
So the given function is y equals y -not cost of t under root k over m.
00:26
In order to find the derivative, we need to apply the product rule.
00:32
So, d -y by d -t becomes d -t -of -y -0 into cos of t under root k over m plus cost of t under root k over m into y -not.
01:02
Since y not is assumed to be a constant, this expression becomes zero.
01:11
Thereby, we are left with d by dt of cost of t under root k over m into y not.
01:29
Now applying chain rule.
01:33
We can assume the inner function u.
01:36
To be equal to t into under root k over m and the after function y equals cause of you.
01:47
Finding the derivative of each of these equations, we get d u by dt equals under root k over m, since k and m both are constants.
02:06
D .y by d u becomes minus 6.
02:10
Of u.
02:12
Hence the equation for d y by d t becomes y not under root k over m into minus sign of u next we simplify and put in the value of u we get minus y not under root k over m sign of t under root k over m for part b we are to find how increasing mass four times affect the derivative thus putting m equals 4m in the equation of derivative you've just evaluated we get d .y by dt equals negative y not under root k over 4m, sine of t under root k over m, 4m.
03:28
On simplification, we get 1 by 2, y not under root k over m, into sign of 1 by 2t under root k over m.
03:45
This implies that the velocity will be half of what originally was, whereas the period is going to be twice of the original...