00:06
In this question, we're given a square box, something that looks like this.
00:16
And we're told that the side is 24 minus 2x.
00:23
The height is x.
00:26
And we're told to find the volume of this box.
00:29
And since it's a square box, we know that if this side is 24 minus 2x, this side is also going to be 24 minus 2x.
00:39
So to find the volume, it's going to be the.
00:44
Area of the square times height, which is the area is going to be 24 minus 2x square and the height is x.
00:57
So therefore, the volume is equals to x into 24 minus 2x square.
01:07
Now, before this shape became a box, we're told that it was simply a square with side 24.
01:15
That was folded.
01:19
So it was folded into about half to make this box.
01:25
So we know that the height x is going to be less than 12, which is half of the length of the side before it was folded.
01:38
We know that that's going to be less than 12, but it's greater than 0.
01:46
Now the next thing we have to do is plot a graph.
01:54
To plot this graph, we have to substitute different values of x to find the different values of the volume so we know that um v is equals to x into 24 minus 2 x so if x is 1 v is going to be equals to 1 into 24 minus 2 which is going to be equals to square which is equals to 484 if x is equals to 2 v is equals to 2 into 24 minus 2 times 2 is going to be 4 square which is equals to 800 if x is equals to 3 v is equals to 2 into 24 3 into 24 3 into 24 minus 3 times 2 is going to give us 6 square, which is equals to 9, 7, 2.
03:09
If x is equals to 4, v is equal to 4 into 24 minus 8 square, which is equals to 10 to 4.
03:26
Let's keep going if x is equals to five v is equals to five into twenty four minus ten square which is equals to nine eighty if x is equals to six v is equals to six into twenty four minus twelve square which is equals to eight six four so now we've gotten sufficient point for x and y so we can now plot our graph this is going to be our x and v is going to be our y values so we have a graph here x y i'm just going to fill in different values for both axes and then we can plot so i've gone ahead and filled in different values um for different exist for the x and the y exist now we're going to plus our graph when x is 1 y is 484 so when x is 1 when x is 1 y is 484 so it's going to be somewhere here that's our first point i'm just going to mark you with x when x is 2 y is 800 so when x is 2 y is 800 so why is 800 so we have this point right here.
05:18
When y is when x is 3, y is 972...