00:01
In this problem, we have to start off by finding the scalar triple product given the vector is uv and w.
00:10
So let's start off by finding v -w.
00:14
V -cross -w, which we can find using the formula listed here, is v -2 times w -3.
00:27
So that's negative 1 times 0, which is just 0, minus v3 times 0.
00:37
W2, that's going to be negative 1 times 0, which is just 0.
00:44
And the second part, v3 times w1.
00:48
V3 is negative 1, w1 is 6.
00:51
That makes this term negative 6.
00:55
And then v1 times w3, w3 is 0.
00:59
Therefore, the second term is 0.
01:02
And for the third part, v1 times w2, w2 is zero, so this can automatically be made zero, minus v2 times w1, that's negative 1 times 6.
01:18
That's just negative 6.
01:22
And now when we simplify this, we get an answer of 0, negative 6, comma, negative 6, comma 6...