00:01
Consider the lovely diagram i've written right here.
00:03
We're told that water 20 degrees flows through a 5 -centimeter pipe.
00:07
I've written all the data down here with the right units on it.
00:12
It has a 180 vertical bend between and the total length between the flanges, 1 and 2 is 75 centimeters.
00:27
We're given the weight flow rates and neglecting pipe weight determine the total force the flanges must withstand for the flow.
00:36
Okay, so first of all, let's find the area, and that'll equal 4 pi.
00:46
Whoops, pi over 4.
00:49
What are we doing? pi over 4 d squared will equal pi over 4 times 0 .05 squared equals 0 .021 meters squared.
01:10
There's my area.
01:13
And then our discharge, and that will be q over this by density times g.
01:43
And so we'll get q equals 230 divided by 998 times 9 .8 and that will equals 0 .0 to three meters cube per second.
02:23
Okay.
02:25
The pipe is the same, so the area is the same.
02:28
So my inlet and outlet velocities, let's see here.
02:42
0 .0233 divided by 0 .00221 will equal 11 .88 meters per second...