00:01
Hi, so this problem was about a water flowing off of a dam at some rate, capital r in units of kilograms per second.
00:12
And the height of the dam is also given, and we note that as lowercase h.
00:21
And we're asked to find out what the power from the water is.
00:28
And we're asked to show that it is equal to capital r, g, h.
00:35
We can start out this problem by figuring out what power is.
00:42
It's in general equal to the change in energy divided by the change in time.
00:49
In this case, the change in energy is equal to the change in potential energy of the water, which is going to be equal to the change in mgh.
01:00
So this is the potential energy divided by the change in time.
01:05
Well, if you rearrange this a little bit and write it down so that delta m and delta t are together multiply by gh, this is just equal to capital rgh.
01:21
So there you go.
01:22
That was part a...