Question
Water gas is produced from the reaction of steam with coal:$$\mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{CO}(g)$$Assuming that coal is pure graphite, calculate $\Delta H^{\circ}$ for this reaction.
Step 1
We are given the reaction: C(s) + H2O(g) → H2(g) + CO(g) We need to find the enthalpy change for this reaction, ΔH°. Show more…
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Water gas is produced from the reaction of steam with coal: $$ \mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{CO}(g) $$ Assuming that coal is pure graphite, calculate $\Delta H^{\circ}$ for this reaction.
Water vapor is passed over coal (assumed to be purc graphite in this problem) at $1000 \mathrm{K}$. Assuming that the only reaction occurring is the water gas reaction \[ \mathrm{C}(\text { graphite })+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})=\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{g}) \quad K=2.52 \] calculate the equilibrium pressures of $\mathrm{H}_{2} \mathrm{O}, \mathrm{CO},$ and $\mathrm{H}_{2}$ at a total pressure of 1 bar. $[$ Actually, the water gas shift reaction \[ \mathrm{CO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})=\mathrm{CO}_{2}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{g}) \] also occurs, but it is considerably more complicated to take this additional reaction into account.
The reaction of heated coal (approximated here by graphite) with superheated steam absorbs heat. This heat is usually provided by burning some of the coal. Calculate $\Delta_{\mathrm{r}} H^{\circ}$ $(500 \mathrm{K})$ for both reactions.
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