Water is pumped between the two tanks cescribed in Example...

Water is pumped between the two tanks cescribed in Example 12.4 once a day, 365 diys a year, with each pumping period lasting two hours. The water levels in the two tanks remain essentially constant. Estmate the annual cost of the electrical power needed to operate the pump if it were located in your city. You will have to make a reasonable estimate for the efficiency of the motor used to drive the pump. Due to aging, it can be expecied that the overall resistance of the system will increase with time. If the operating point shown in Fig. $\mathrm{E} 12.4 \mathrm{c}$ changes to a point where the flowrate has been reduced to 1000 gpm, what wil be the new annua cost of operating the pump? Assume that the cast of electrical power remains the same.

Key Concepts

Effects of Aging on Pump Performance

Over time, physical factors like wear and tear can lead to increased resistance in the pumping system. This concept encompasses how aging affects system dynamics, leading to changes in the operating point (e.g., reduced flow rate) and consequent adjustments in the energy usage and cost required to maintain performance levels.

Hydraulics Performance and Flow Rate

This concept pertains to the relationship between the pump’s flow rate and its operational characteristics, such as the hydraulic head and overall power requirements. Changes in the flow rate, such as a reduction from original operational conditions, signal variations in the system performance, which in turn affect energy consumption and cost estimations.

Motor Efficiency

Motor efficiency is central to understanding how effectively electrical energy is converted into mechanical work by the pump. This concept is essential because any losses in efficiency directly affect the energy needed from the electrical supply, thus impacting the overall energy consumption and cost. A reasonable estimate for the motor's efficiency is necessary for accurate cost estimation.

Energy Consumption Estimation

This key concept involves calculating the total energy used over a period by integrating the power requirement during operation. It requires converting operating time into total hours over a year and multiplying by the pump’s power usage, while factoring in the cost per unit of electrical energy to derive the overall operating cost.

Pumping System Operation

This concept covers the scheduled operation of a pumping system that transfers water between two tanks. It involves understanding the frequency (daily) and duration (hours per day) of pump usage, which is crucial for calculating the energy consumption and ultimately the annual operating cost of the system.

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