00:01
Okay, so based on the table a4, which is the table of saturated water temperature table, we know that the initial volume of the water at 15 degrees celsius should be equal to 0 .001 kilogram per meter cube.
00:19
So therefore, we can determine the velocity, which is the inlet velocity here, is equal to mass flow rates times the initial volume at 15 degrees celsius, and over the initial air, area, which is equal to m.
00:33
Times v1 at 15 degrees celsius over pi times d1 over 2 square.
00:37
D1 is the diameter at the beginning.
00:40
Okay? so we know mass flow rates is given as 0 .5 kilogram per second and we know the initial diameter is 1 centimeter, which is 0 .01 meter.
00:51
So therefore if we plug in battery equation, we'll have the inlet velocity at 15 degrees celsius is equal to 0 .5 kilogram per second and times 0 .0 .01 1 .0 .01 kilogram per meter cube over pi times d1 over 2, which is 0 .01 meter over 2 to the power 2.
01:35
And this will give us the inlet velocity is about 6 .37 meter per second.
01:43
So when the outlet velocity should be equal to the inlet velocity times the a1 over a2, which is the initial area over the final area, which can be expressed as pi times d1 over 2 to the power 2 over pi times d2 over 2 to the power 2.
01:59
As you can tell, pi can be canceled out and 2 here can be canceled off...