Water rises in a vertical capillary tube up to a length of $10 \mathrm{~cm}$. If the tube is inclined at $45^{\circ}$, the length of water arisen in the tube will be
(A) $10 \sqrt{2} \mathrm{~cm}$
(B) $10 \mathrm{~cm}$
(C) $10 / \sqrt{2} \mathrm{~cm}$
(D) None of these