00:01
All right, guys, the general form of the reaction can be written as h2o, then reaction sign, then ah2o plus bh2 plus c -o2 plus do8.
00:20
So the hydrogen and oxygen balance give the following two equations for the coefficients.
00:25
So equation 1 is 1 is equal to a plus b plus 0 .5d.
00:34
This is equation 1.
00:36
And then we have 0 .5 is equal to 0 .5a plus c plus 0 .5d.
00:45
Guys, this is our equation 2.
00:47
The two stoichiometric reactions relevant to this example and their corresponding equilibrium coefficients taken from table, for the given temperature are h2o reaction sign then h2 plus 0 .502 natural log kp1 is equal to minus 3 .086.
01:17
Similarly, h2 reaction sign 0 .5h2 plus oh natural log kp1.
01:29
Is equal to minus minus 2 .937.
01:37
Now moving further, the equilibrium coefficient relations give the next two equations for the reaction coefficients that is e raised to power minus 3 .086 is equal to b under root c divided by a under root a plus b plus c plus t so guys this is our equation number three and similarly e raised to power minus 2 .937 is equal to d under root b divided by a under root a plus b plus c plus d.
02:24
Now what we do, the equation 1, 2, 3 and 4 are solved simultaneously using the wolfram alpha and their solutions and the equilibrium compositions.
02:36
Are a is equal to 0 .7835, b is equal to 0 .1622, c is equal to 0 .0540, d is equal to 0 .1086...