Question
We can draw two tangents from the point $\mathrm{P}$ to the circle $|\mathrm{z}+5+2 \mathrm{i}|=2$. The right choice for the coordinates of $\mathrm{P}$ from the following is(a) $(-7,-2)$(b) $(-6,-4)$(c) $(-4,-3)$(d) $(-6,-3)$
Step 1
We can rewrite this equation in terms of x and y as $|(x+5)+(y+2)i|=2$. Show more…
Show all steps
Your feedback will help us improve your experience
Uma Kumari and 91 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If the tangent at the point $P$ on the circle $x^{2}+y^{2}+6 x+6 y=2$ meets a straight line $5 x-2 y+6=0$ at a point $Q$ on the $\mathrm{y}$ - axis, then the length of $P Q$ is (a) 4 (b) $2 \sqrt{5}$ (c) 5 (d) $3 \sqrt{5}$
Angle between the tangents to the curve $y=x^{2}-5 x+6$ at the points $(2,0)$ and $(3,0)$ is (a) $\frac{\pi}{2}$ (b) $\frac{\pi}{6}$ (c) $\frac{\pi}{4}$ (d) $\frac{\pi}{3}$
The Tangent and Normal
Level II
From a point on the line $4 x-3 y=6$, tangents are drawn to the circle $x^{2}+y^{2}-6 x-4 y+4=0$ which make an angle of $\tan -1 \frac{24}{7}$ between them, the coordinates of such points are (A) $(0,2)$ (B) $(0,-2)$ (C) $(6,6)$ (D) $(-6,6)$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD