Question
We can find the coefficients in the expansion of $(a+b)^{n}$ from the $n$ th row of ______ triangle. So $(a+b)^{4}=\mathbb{I} a^{4}+\square a^{3} b+\square a^{2} b^{2}+\square a b^{3}+\square b^{4}$
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Pascal's triangle is a triangular array of the binomial coefficients. Show more…
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We can find the coefficients in the expansion of$(a+b)^{n}$ from the nth row of __________ triangle. So $(a+b)^{4}=\square a^{4}+\square a^{3} b+\square a^{2} b^{2}+\square a b^{3}+\square b^{4}$
Sequences and Series
The Binomial Theorem
We can find the coefficients in the expansion of $(a+b)^{n}$ from the $n$ th row of _____ triangle. So $$(a+b)^{4}=\square a^{4}+\square a^{3} b+\square a^{2} b^{2}+\square a b^{3}+\square b^{4}$$.
To expand$(a+b)^{n},$ we can use the __________ Theorem. Using this theorem, we find the expansion$(a+b)^{4}$= $\left(\begin{array}{l}{\mathbb{ }} \\ {\mathbb{ }}\end{array}\right) a^{4}$ +$\left(\begin{array}{l}{\mathbb{ }} \\ {\mathbb{ }}\end{array}\right) a^{3}b$+$\left(\begin{array}{l}{\mathbb{ }} \\ {\mathbb{ }}\end{array}\right) a^{2}b^{2}$+$\left(\begin{array}{l}{\mathbb{ }} \\ {\mathbb{ }}\end{array}\right) ab^{3}$+$\left(\begin{array}{l}{\mathbb{ }} \\ {\mathbb{ }}\end{array}\right) b^{4}$
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