We consider the scattering of free particles of mass $m$ that move in one dimension in the potential $V(x)=-W \delta(x)$, with $W>0$. (a) For a well of finite depth $V_{0}$ and width $2 a$ the condition on the phases $\phi$ and
$\phi^{\prime}$ of the even- and odd-parity wavefunctions $\psi \propto \sin (k x+\phi)$, etc., for free particles are
$$
\tan (k a+\phi)=-\frac{k}{K} \cot (K a), \quad \tan \left(k a+\phi^{\prime}\right)=-\frac{k}{K} \tan (K a)
$$
Show that in the limit $a \rightarrow 0, V_{0}=W / 2 a \rightarrow \infty$ we have $\tan \phi \rightarrow$ $-\hbar^{2} k / m W$ and $\phi^{\prime} \rightarrow 0$. Hence obtain the scattering cross-section by the $\delta$-function potential
$$
\sigma=\frac{2}{1+(\hbar k / m W)^{2}}
$$
(b) Re-derive the equation above for $\phi$ by requiring that $\psi=\sin (k|x|+\phi)$ satisfy the TISE. Convince yourself that $\psi=\sin (k x)$ is also consistent with the TISE.