00:01
So we have over here an electron trapped a quantum dot which acts like an infinite square well.
00:13
And the infinite square well starts on the left at x equals to 0, and its length is about 1 nanometers.
00:27
What we want to find is for two different states, right, and it goes to 1 state and then it goes to 2.
00:34
What is the probability of finding the electron between x1 and x2 where x1 is at 0 .15 nanometers and x2 is at 0 .35 so regardless of the state it's what we have to do is to just take the probability density function which is just side square integrated cross dx from 0 .15 nanometers to 0 .35.
01:14
So what are the wave functions for the infinite square well? well in general, it's a square root of 2 over l times sine x over l.
01:32
So this is a general, sorry 2 pi.
01:36
And this not 2 pi sorry this should be n pi it's for general n wave function so the wave function pattern that we want to sketch out for p1 this would be sorry for si1 this would be when our function it has n equals to 1.
02:35
So throughout this entire length it will only have one half of the wavelength.
02:49
On the other hand for the second with function side 2 to be right n equals to 2 pi x then you have a full wavelength throughout the entire box.
03:09
Alright and so on the other hand for the probability density functions.
03:24
Okay at sight 2 square and sigh 1 square.
03:42
So for sight 2 square, when we absolute square it, we bring all the positive values up to the positive side.
03:53
So we'll get two picks and the middle one must reach 0, the 0 point, because basically it touches 0 at this point, right? so definitely 0 square is to 0 on the other end for side 1 because it's already all positive we are just basically increasing the magnitude right so that's all it's a probability density function for side 1 now we can find what is the actual probability for the n equals to 1 state the actual probability of finding the electron right we do the so remember that l is 1 nanometers, the length, and n equals to 1.
05:34
Now using the equation 41 .6, which is written in the question itself, it will help us with the integral.
05:48
Looking at sine square, sine square, a x, bx, right, where a, in this case it's just pi over 1 ,000, nanometer...