00:05
In this question we are asked why the methyl protons labeled a here will give rise to a triplet signal in its proton nmr spectra rather than a doublet of tablets which is expected from the neighboring non -equivalent diastereotropic hydrogens labeled b and c here.
00:29
So this is the case because the coupling constant for splitting the methyl, protons by the b proton which is symbolized jab is very close to the coupling constant for the splitting of a protons by the c protons.
01:05
So if that's the case, the splitting diagram will look like this.
01:09
If we consider the splitting of the a protons, they will first be split into two due to the b protons, let's say.
01:24
So there's one b proton.
01:26
So n plus 1 will be 1 plus 1, which is going to be equal to 2, and the number of peaks that you get from the coupling of a by b is going to be 2 for that reason.
01:44
And the coupling constant here will be equal to j.
01:53
A, b, and then these protons again split from the effects of the c proton...