Problem

Find $C$ when $F$ is $32^{\circ}$.

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Problem 22 Easy Difficulty

We have mentioned the two temperature scales, Fahrenheit and Celsius. Table 1 is intended to give you a more intuitive idea of the relationship between the two temperatures scales.
(TABLE CANNOT COPY)
Table 2 gives the formulas, in both symbols and words, that are used to convert between the two scales.
(TABLE CANNOT COPY)
Let $C=37$ in the formula $F=\frac{9}{5} C+32,$ and solve for $F$ Does the value of $F$ agree with the information in Table $1 ?$

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Video Transcript

here. The relation between the Celsius and Fahrenheit is given by the equation. F is equals to nine by for you see plus off 32. So we have to complete the table where we are given with certain values off, see and certainly leaves off half. So we have to find the other values. Let's start with See is equal to minus off 30 degree, so we will have f physical store nine by five Endo minus off 30 plus off 32. So we will have the value is is it closed toe? 90 doe minus off six plus off 32. So we will have is it goes toe minus or 54 plus off 30 dough. So this will be coastal minus off 22 degree firing height. You know, let's even see is a close to minus off 20 degree. We will have f is equals to nine by five Indo minus off 20 plus off 32 F vehicles to 19 to minus off four plus off 30 dough or this will be close to minus off 36 plus off $30 or this will be a close to minus off four degree fighting height. No. Let's check develop when C is equals to minus off gen degree so we will have f is equals to nine by five and don't minus off 10 degree plus off 32. So this will vehicles to 19 to minus off two plus off $30. But this will vehicles to minus off 13 plus off 30 dough or is equals to 14 degree friend in height. No, there's check diluted when sees equals 20 degree so it will have f is it calls to nine by five endo zero degree plus off 32. So this implies that we will have f is equals to 32 degree Now now then we will have f is equals to 50 degree. We have to find the value of C. So 50 degree will be close to nine by five C plus off 32 or we will have 250 degree. Is it closed toe 90 plus off 30 Dough or we will have 90 is a coastal 2 50 minus off Ardito. So this will be close to in tow five. So we'll have nine sees equal sto. 250 minus off 1 60 So we will have 90 is equals to 90 or we will have C is equals to then Nigari. No, let's check the case when we have is it goes to 60 year degree so we will have sees equals two 60 year degree is equals to nine by five C plus off 32 degree What We will have 68 into five Is it closed toe? So this will be close to nine c Bless off 1 60 degree. So from here we will have 340 minus off 1 60 is equal to nine c What we will have when it to duty Is it close to 90? Or from here we will have sees equals two 20 degree? No, let's consider the case Then we are given with F is equal sto 36 daily. So we will have 36 degree physical store nine by sea nine by five See plus off 30 degree Or we can say that we will have 430 degree is it goes to 90 bless off 1 60 degree or we will have 90 Is it questo? 200 sound pretty. So here we will have C is equals to 30 degree. So here we have find all the values for the city in which it is given and values off f where C is given. No, we have to find the values. Were the temperature skills agree? So let's going to consider that we have f is equals. Two c is equal stow a So we will have a physical store nine by five a bless off 32 or we will have five. A plus off. Is it closed toe? Nine. A. Bless off 1 60 What? We will have nine a minus or fire ravages 40. Is it closed toe minus off 1 60 degree or we will have is equals to minus off 40 degrees. So at minus 40 degree we will have is equals to see

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Problem

Find $C$ when $F$ is $32^{\circ}$.

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Video Transcript

Charles P. McKeague

Prealgebra

Grace He

Catherine Ross

Caleb Elmore

Michael Jacobsen

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Prealgebra

Grace He

Catherine Ross

Caleb Elmore

Michael Jacobsen

Charles P. McKeaguePrealgebra

Grace He

Catherine Ross

Caleb Elmore

Michael Jacobsen

Charles P. McKeague

Prealgebra