00:01
So we are given the following reaction.
00:03
We see that we have a bromohydrid being converted into an epoxide with treatment of a base.
00:12
And we want to propose an arrow -pushing mechanism that explains what's going on here.
00:17
So what we see here in our first step is our hydroxide is actually going to come in and deprotonate at the alcohol.
00:25
So we can go ahead and draw that real quick.
00:33
So we have the following.
00:52
So we're going to have our first step here is...
01:02
So our hydroxide, or sodium hydroxide is going to come in, it's going to deprotonate at the hydrogen here, and these electrons are going to go to the oxygen.
01:10
So that gives us the oxygen anion here.
01:36
And i'm going to go ahead and label these carbons, because we'll see in the next step here, i'm just going to orient us.
01:42
So we're going to see that this is carbon number one, this is carbon number two, this is carbon number three, and this is carbon number four.
01:50
And so what we see here when we do this step is we're going to have a rotation.
01:57
Oops, sorry.
02:01
So we're going to have a bond rotation at carbon number two...