00:01
Okay, so for problem 22, we're given the opposite of problem 21.
00:05
Okay, we're given the resulting mixture of compounds when we subject this unknown, for now it's unknown, unknown 5 carbon sugar.
00:19
And we subject it to the killianney -fisher reaction.
00:24
Okay, so h2 and your catalyst.
00:28
And of course you have that acid okay so when we subject this five carbon sugar into that reaction we know that we are adding another carbon which ends up to be an aldehyde and this oh h group is going to either the left side or the right side okay so knowing that we know that this part of the structure is what we added from the reaction okay and this carbon this carbon right here is what originally was the aldehyde okay so since it is what was originally the aldehyde i'll number it carbon number one okay so that means this is carbon number one right here one two three four five okay so the same is true for these structures on the right this carbon with the blue dot on it would be your carbon 1, okay? and so on, four, and same thing for this one.
01:43
And we do see that carbon number 1 is what made a difference between these two molecules.
01:51
So you could ignore that for this problem because when you get that 5 carbon sugar, you have the aldehyde, okay? so it's not going to have that chirality anymore.
02:02
So what we're doing here is we're going to cause.
02:04
Copy carbons 2 to 5...