00:01
In this problem, we are trying to find the empirical formula of the compound.
00:10
So for the first one, we are given that this is 40 .1 % carbon, 6 .6 % hydrogen and 53 .3 % oxygen.
00:25
When we're given the mass percent of each element in the compound, we have to assume 100 grams of the compound.
00:35
Then in 100 grams of the compound, the mass of each element is equal to the mass percent of each element.
00:43
So we're going to convert from the mass to moles of each element.
00:48
So we have 40 .1 grams of carbon, divide by 12 to get moles of carbon.
00:59
We do the same thing with hydrogen.
01:01
We use the atomic mass of hydrogen to get moles of the hydrogen.
01:05
And for oxygen, we use the atomic mass of oxygen to get moles of oxygen.
01:11
Then we're going to divide by the smallest number of volts that we have calculated.
01:17
And this gives us the subscript of each of the elements in the formula.
01:21
So you need to round to the nearest whole number...