00:03
This is the answer to chapter 13, problem number 18, from the smith organic chemistry textbook.
00:12
And this problem is asking us to look at six molecules and to predict what kinds of ir signals we're going to see.
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And so to start, so each of these molecules has csp3h bonds.
00:31
So sp3 carbons bonded to hydrogens.
00:35
And so all of these molecules are going to have peaks at 2850 to 3 ,000 wave number.
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And so for a, that's actually all the peaks that it's going to have.
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Remember, ir tells us about functional groups, and there are no functional groups in molecule a.
00:54
So it's only going to have those csp3h peaks.
01:00
So then when we look at b, the functional group that we see in b is an alcohol.
01:06
And so alcohol is going to be a broad signal at 3 ,200 to 3 ,600 wave numbers.
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And so i've just, i've written where the peak will be in red, and i've written the functional group that it represents or the bond that it represents in blue.
01:24
And so moving on to c, the only functional group in c is a functional group in c is a functional group.
01:29
An alkene, a double bond.
01:32
And so remember, as long as there are hydrogens on any of the carbons involved in a double bond, you're going to get two signals.
01:43
You're going to get the signal for the carbon -carbon double bond, which is going to show at 1 ,350 wave number.
01:51
And you're also going to get the signal somewhere between 3 ,0301 .50 wave number for the csp2 hydrogen bond.
02:04
And so that's for c.
02:06
Again, there will be two major peaks in addition to the peak, you know, that all of these have for the csp3h bonds.
02:16
So moving on to d, the functional group in d is a ketone.
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And we know ketones show somewhere in the vicinity of 1700 wave number.
02:27
And so that's the answer to d.
02:29
And then moving on to e, e is a little bit more complex of a molecule.
02:34
And there are two functional groups in a...