00:06
Let's calculate the major species present and the ph of a .250 molar solution of the following acids.
00:13
For a, we have c6h5oh, which is a weak acid.
00:20
And the major species present would be c6h5oh and h2o.
00:34
Since it is a weak acid, we need to construct an ice table.
00:51
Initially we have 0 .250 molar minus x computer ice table based on our ice table we can write our k a expression substitute our values in we can look up the k a for c6h5 oh which will be 1 .6 times 10 to the minus 10 is equal to x and x over 0 .250 minus x being a weak acid x is going to be very small 0 .250 minus x, approximately equal to 0 .250, 0 .250.
01:43
Simplifies us from solving a quadratic equation.
01:49
Solving for x here yields 6 .3 times 10 to the negative 6.
02:03
So our ice table defines x as the molarity of h .30 plus, 6 .3 times 10 to the negative molar.
02:10
Therefore, the ph would be negative log.
02:14
6 .3 times 10 to the negative 6 .6.
02:17
And solving for our ph here.
02:20
We get a ph of 5 .20.
02:27
For b, we have hcn, which is a weak acid...