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What are the mole fractions of $\mathrm{H}_{3} \mathrm{PO}_{4}$ and water in a solution of 14.5 $\mathrm{g}$ of $\mathrm{H}_{3} \mathrm{PO}_{4}$ in 125 $\mathrm{g}$ of water?(a) Outline the steps necessary to answer the question.(b) Answer the question.

a. The mole fraction $=\frac{\text { Number of moles of component }}{\text { total number of moles of all component }}$b. 0.021 , 0.979

Chemistry 102

Chapter 11

Solutions and Colloids

Solutions

University of Central Florida

University of Kentucky

University of Toronto

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Hello, everybody. This is Ricky. And today we're working on problem number 30. And for this we have to calculate the mole fractions of each Threepio four and water in a solution of 14.5 grams of H threepio four and 125 grams of water. Okay, so first we have to calculate e number of moles of each. So let's go steps. One calculates number of moans in a solution. And we can do this by going moves equal to e mass times the molar mass or one over rather dividing by the molar Mass. Then next we calculate more fraction. And this is equal to, um, morals of part over total moons. All right, now, let's plug in our numbers. Let's go for so the mass of H three PS four is 14.5 grounds times by its are divided by Muller Mass, which is 98 grams. And so we get that there are 0.15 moles of each. The repeal four. Next, let's look at water. So we have under 25 grams of water divided by its more mash of 18 and we get 6.94 moles, water um, let's just some these right now to get the total number of moles. Um, that would be 7.9 total, and we can calculate our mole fraction now. So for age Threepio four, we have 0.15 over 7.9. We get, um, 0.21 each. Threepio four. When we do the same thing, water where we can subtract by one. Either way works. Um, so we get 6.94 moles H 20 oh, for 7.9 miles total. When we get about 0.979 more traction of water. So I hope this video is helpful.

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