00:01
This problem gives us the density of the gas and it tells us it's at standard temperature pressure, and it's asking us to find the molar mass.
00:08
And then for this problem, it gives us the density of the gas, and then it gives us a specific temperature and pressure, and it's also asking for the molar mass.
00:17
So for this problem, first, we know that pressure is equal to 1 .e .m.
00:24
Because it's standard temperature and pressure.
00:26
We know that temperature is 273 kelvin.
00:30
And then volume is equal to one liter.
00:34
So this kind of is hidden inside the problem.
00:37
And you can make this volume whatever, but it makes it easiest if you say one liter because it'll cancel this out.
00:43
And so then n, n, so we don't have the number of moles, but we can sort of find it.
00:51
So 1 .32 grams, and let's just pretend that we multiply by one liter, so it cancels it out.
00:59
And then we can use the molar mass to convert to this to moles.
01:06
And that's what we're trying to find, is the molar mass.
01:09
So let's assume that we do have it, and let's label x.
01:14
So the molar mass is the same thing as grams per mole.
01:23
So we need to divide by the molar mass, because we want grams on the bottom so that this cancels.
01:29
So, rn is equal to 1 .342 divided by this x, which is the molar mass.
01:41
Because this value will be in moles, which is what n needs to be in.
01:49
So now we can use the ideal gas law and solve...