What charge exists on a test charge that experiences a force of 1.4 ×10^-8 N at a point where th

step 1 Okay, so the electric force is equal to charge times the electric field. If we do some arrangeme

Question

What charge exists on a test charge that experiences a force of $1.4 \times 10^{-8} \mathrm{N}$ at a point where the electric field intensity is $5.0 \times 10^{-4} \mathrm{N} / \mathrm{C} ?$

   What charge exists on a test charge that experiences a force of $1.4 \times 10^{-8} \mathrm{N}$ at a point where the electric field intensity is $5.0 \times 10^{-4} \mathrm{N} / \mathrm{C} ?$

Physics Principle and Problems

Paul W. Zitzewitz,… 1st Edition

Chapter 21, Problem 66

Instant Answer

Solved by Expert Dading Chen

05/28/2020

Step 1

Step 1: The electric force is given by the equation: \[ F = qE \] where $ F $ is the force, $ q $ is the charge, and $ E $ is the electric field intensity. Show more…

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What charge exists on a test charge that experiences a force of $1.4 \times 10^{-8} \mathrm{N}$ at a point where the electric field intensity is $5.0 \times 10^{-4} \mathrm{N} / \mathrm{C} ?$

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Key Concepts

Electric Field Intensity

Electric field intensity is a measure of the force experienced per unit positive charge at a point in space. It defines the strength and direction of the electric field and is expressed in units of newtons per coulomb (N/C). This concept is fundamental in understanding how charges interact in space and is used to describe the influence a source charge or distribution of charges has on other charges in its vicinity.

Force on a Test Charge

The force experienced by a test charge in an electric field is directly proportional to both the magnitude of the charge and the electric field intensity. This relationship is expressed by the formula F = qE, where F is the force, q is the charge, and E is the electric field intensity. This concept is crucial for calculating the behavior and dynamics of charges when placed in external electric fields.

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