what-differences-do-you-predict-if-you-use-uv-sensitive-paper-to-test-sunglasses-with-uv-protection-

Name: what differences do you predict if you use uv sensitive paper to test sunglasses with uv protection
Uploaded: 2020-10-17
Duration: 58 s
Channel: Numerade
Description: What differences do you predict if you use UV-sensitive paper to test sunglasses with UV protection compared with regular reading glass without UV protection?

Question

What differences do you predict if you use UV-sensitive paper to test sunglasses with UV protection compared with regular reading glass without UV protection?

Madi Sousa · Accepted Answer

in this problem, we have to compare how you the paper would react under two different sources of glass. The first one are sunglasses, So sunglasses have UV protection. Remember, because we wear them to protect your eyes from the sun so the sunglasses air going to block any UV light going on to our UV paper. So we&#x27;re not going to see any color Jane color change. Excuse me with sunglasses, however, if we use regular glasses, Regular glasses have no view protection. So we&#x27;re going to see a transfer of energy onto our UV paper, and it&#x27;s going to excite all of our electrons on our paper and the U V paper will turn color and we&#x27;ll see it change to blue. So I hope that this problem helped you understand how UV paper would react under two different sources of glass

Sanjeev Kumar · Answer

now look in the skies to the polarizing glasses Noticed that some places the brightness off blue sky in some places The brightness off you sky Jim, do as you rotate the polarizer as you Rudy the polarize it That is because the light in the sky is polarized Night in the sky is polarised

Ben Nicholson · Answer

29.56 s. So why is the Polaroid polarized sunglasses can reduce glare, whereas non polarized sunglasses, uh, just produce the total amount of light reaching the eyes. And the reason is that, um, you have something like the surface of water say, when might reflects off of it and, you know, creates Blair. This consists of un polarized light, which has sort of vertical and horizontal components. But when it reflects off of a surface in this way on Lee, the horizontal component remains, or sort of from the point of view of someone observing this. You have the vertical and horizontal components, and then one it&#x27;s reflected only the horizontal component is left, and so polarized sunglasses have their access of polarization vertically. And so this reflected light that causes Blair gets blocked. And whereas if they were non polarized than they&#x27;re just sort of absorb some amount of light but don&#x27;t change but don&#x27;t block, uh, any particular direction of polarization. And so the facts that glare is mostly horizontally polarized. Uh, you know, it can&#x27;t eliminate that

Ashima Tiwari · Answer

Okay, So for this question were given an equation and were asked to use trial and error to determine the unique index when the lenses are 50% transparent. So basically, using trial and error, we need to figure out X equals. So because they&#x27;re using trial and error, I&#x27;m not going to go through the mathematical way to isolate X and solve for that, um, we know that T X equals since his 50% it&#x27;ll be 25. So what we can do is basically, maybe come up with, like, a table of X values that we can plug in that will give us a T X value of 0.5 something pretty close to it. So let&#x27;s just go for Oh, maybe one, 2345 So I would really just pull these cack values in. So this would be easier of 25 so that that isn&#x27;t right. Obviously, um, this would be around your 0.73 again, not really close. Um, then we can plug in the next fall you to your 0.61 getting closer. So maybe we can estimate that it will be around four or five and then Okay, So when you plug in for you gets your 0.5 to I would imagine that if you called in five, you would get something a little further away. Bullets will get in just to write it down. Yeah, you get your point for. For so using trial and error, we can say that the UV Index is around for And if we maybe want to be more specific, maybe we can try plugging in increments of force. Maybe like 4.2 by were 4.5. You can try that. It is true that. Okay, so I&#x27;ve found that this equals around four point. Means your point worried, and then this equals actually around 0.50 So we clearly have a winner over here. So we can say that using trial and error, the UV index is probably going to be around or point 25

Ashima Tiwari · Answer

Okay, So for this question, we are given in equation and all we really need to do is apply what&#x27;s given in the problem to this equation under answer. So we were asked to find the transparency to the nearest percent. If the lens of they&#x27;re exposed to a sunlight with UV index of 11 it&#x27;s asking for the minimum transparency percentage for these type of lenses. Um, so really, all we need to do since X is, uh, stance for the UV index. In this case, we need to just substitute different color. I need to put in 11 in Forex and we are given an A from like our calculator that we get one point around. How? Excuse me around 0.17 So what? It asks us to find it in the nearest percentage. So all we need to do to convert this a percentage is multiplied by 100%. This will give us around 17%. Minimum transparency would be needed

Ashima Tiwari · Answer

Okay, So this problem, you&#x27;re given an equation and all we have to really do is apply the information given to us from the problem into this equation. So were asked to find the transparency to the nearest percent if the lenses are exposed to sunlight with the UV index of 5.5. So all we really have to do is substitute by 0.5 into this equation for X. So when you put that into the calculator, you&#x27;ll get zero point or one and saying but ST to nearest percent. So in order to convert this to a percentage always to do is want to buy this buy 100% and we&#x27;ll get on 41 percent transparency.

Problem

Write a lab report for the experiment that you de…

Problem 7 Easy Difficulty

What differences do you predict if you use UV-sensitive paper to test sunglasses with UV protection compared with regular reading glass without UV protection?

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