what-evidence-shows-that-it-would-be-dii-cult-to-exceed-the-lethal-dose-of-aspartame

Name: what evidence shows that it would be dii cult to exceed the lethal dose of aspartame
Uploaded: 2020-10-16
Duration: 1 min 48 s
Channel: Numerade
Description: What evidence shows that it would be dii cult to exceed the lethal dose of aspartame?

Question

What evidence shows that it would be dii cult to exceed the lethal dose of aspartame?

David Collins · Accepted Answer

question Number two asks you to review the discussion in this section that the author provides for the lethal dose of fructose. Compared to the lethal dose of Asper Tain, the author gives a pretty good discussion, explaining that the lethal dose for fruit doses 0.158 moles per kilogram, or 0.0 34 moles of aspartame per kilogram. So it appears that the aspartame is about three times as are five times as lethal, um, requiring 1/5 the amount in order to reach the LD 50 level, however, because we consume so much less aspartame per the food containing aspartame or the beverage containing aspartame, Um, for example, 40 g of fruit dose or in a can of soda pop, but only 400.2 to 5 g are in a diet sort of pop of aspartame. It just becomes near impossible to consume enough food or beverage that contains aspartame in order to reach the LD 50 level. Okay, the calculation was shown that we would have Thio drink 2884 cans in order to reach the lethal dose, while it would only take 41 cans of regular sort of pop to reach its lethal dose, So there&#x27;s pretty good evidence that we just can&#x27;t consume enough food or beverages with aspartame to reach its lethal dose.

Joanna Quigley · Answer

what a diet avoids phenylalanine containing compounds, but this is B p K u Doubts diet for treating mental kita area. And could you have a spots me with this die? It&#x27;s probably not because of spots me contains a small amount of melanin and invest. So if you want to include as little as possible, so no spots if you want to avoid this particular chemical, most of your food is going to be a protein, fruits and vegetables, um, breads and pastors and then very Lessel of any animal products one butts.

Carlene Jimenez · Answer

this question asks which vitamin is essential in metabolism, so vitamin B six part Doxil is essential and metabolism as it is, a precursor to paradox phosphate coenzyme, required by all enzymes which catalyze amino transferees reactions.

Carlene Jimenez · Answer

So this question wants us to answer a lot of questions about aspartame. Um, and who are we can start to answer some of them. We must first figure out what is the molecular weight of Aspar team. And we can figure that out from the chemical formula by something we weights of the um Adams, which make it up. So it&#x27;s made up of 12 14 carbon atoms, 18 hydrogen atoms, two nation Adams in five oxygen atoms. And that gives us a molecular weight of 294.34 grams per mole. Now the president wants to know how many milligrams of aspartame are in 3.72 times 10 to 26 molecules of Aspar team. And before we can do this mean to figure out how many mole are in that many molecules. And we can figure that out by dividing the number of molecules of Aspar team by other God Drew&#x27;s number. And that gives us a total of 617.73 Mol, Um, another question wants us to find out how many milligrams of aspirin team there are, But first we need to find out how many grams of aspartame there are given that number of mole. So we have to refer back to the conversion triangle, which gives us the relationship between a mass of a compound, the number of moles of a compound and that compounds molecular weight and to find the mass of a compound. Given its number of moles and molecular weight, we just have to take the product of the number of roles at its molecular weight. So, um, for the amount of ascertain we have, we just multiple I 6 617.73 mol of Aspar team with the molecular weight of Aspar team, which is 294.34 grams Permal. And that gives us 1000 um, 181,000 181,800 um, and 24.116 grams of Aspar team, which we can convert to milligram by multiplying it by 1000. Now the question wants us to determine, um, how you only call you. How many well heels of aspartame are in a 25 milliliters sample of ascertain with a density of 1.35 grams per mil eater. So first we want to know how many grams of Aspar team we have. Um let me figure that out by multiplying the volume of ascertain we have by the density of Aspar team. And this tells us that we have 30 3.75 grams of Aspar team and now the question want. And now we have to figure out, um, how many mole of aspartame are in that sample and we can figure that out by get referring to or conversion triangle, which tells us that the number of moles, um, can be found by dividing the weight of a sample. Ingram&#x27;s, um, by the molecular weight of the compound. So the molecular weights, as we calculated previously it was 294.34 grams per mole. And this tells us that we have a total of 0.11 for seven mole of aspartame. And now the question wants us to report how many molecules of aspirating we have. And we can figure this out by multiplying the number of mold Vasbert team by other God. Girls number and we figure out that a 25 millimeter sample of aspartame contains, UM 6.91 times 20 times 10 to the 22 molecules of Aspar team. Now the question wants to know how many Haijun Adams are present in a one milligram sample of Astro team. Um, and we can just before can answer this. Let&#x27;s just quickly convert it from one milligram aspirin team to one times 10 to the negative three grams of aspartame. We got this just by dividing, um, it by 1000 which is the conversion rate between grams and milligrams. So the number of mole ah Aspar team in one milligram kidney found by again referring to our conversion triangle, which tells us that the number of moles is found by dividing the weight by the molecular weight. Um, so we will divide are one time send to negative three grams of aspirin attained by its molecular weight to just 294.34 grams per mole. And we find that one milligram vast per team contains 3.39 seven times 10th and later six small of Aspar team and the number of mole of hydrogen atoms in Ask pertain is actually equal to 18 times the number of mole of Aspar team, and this is because one single mole of Aspar team contains 18 mole. One mole of aspartame contains 18 mole of hydrogen atoms because that is how many atoms are in the composition of Aspar team in just one molecule of it. So we&#x27;ll just multiply the number of full of ask pertained by 18 to get the number of all of Hydra Adams, and we will find that it contains six times 6.12 times 10 to the negative five, uh, moles of hydrogen atoms and to get the number of, um, Adams total because right now it is being reported in units of mole. We just have to multiply this value a certain number of Adams. It&#x27;s found by multiplying the number of mold. Um, and we multiply this number of bull by of a God rays number. Then we find that, um, in one milligram of aspartame, there contains 3.68 times, 10 to the 19 Haijun Adams. Um, next, this question wants us to fill be following Dia groom for the skeletal structure of aspartame, which is missing. It&#x27;s double bonds, triple bonds and or lone pairs. Um, so we can fill that in quickly, just from context clues and the number of hydrogen ins that each carbon atom is bound to. We know that this must be a benzene ring. Um, and we know that this must be some Esther group, and we can fill in the lone pairs on the oxygen. Um, similarly, we know that this must be on a meid group. Um, and we can also fill in the lone pairs on the Austin Adams, and we know that on the right most, and here must be a car box of the group, and we can similarly fill in the lone pairs. Next, The question wants us to, um, identify the geometries present on each central atom of aspartame using Vesper theory. Um, so if we look at the skeletal structure of Aspar team, um, we can begin to identify which compounds Oh, sorry. I realized I was missing a hike in here. We can begin to identify which compounds have, um, s p three hybridization. So, um, the compounds which have sp three hybridization Sorry. The Adams, which have SP three hybridization, are as follows, and we can tell this based off of the number of atoms they&#x27;re bound to. And if they have any lone pairs Um Oh, actually missing Ah, on a might group here. Um, but this carbon is also sp three hybridized, as is the carbon which is adjacent to it. Um, and those Adams with SP Sri hybridization our touch a huge role, Um, and all other Adams and ask pertain. So all of the other Adams in Aspar team are sp two hybridized, so we&#x27;ll circle them. It&#x27;s only the ones that I&#x27;ve squared off in purple, which RSP three hybridize and have a tetra hydro. Um shape all of the other atoms and aspartame. RSP to hybridized. Um, and they all of their bonds exist on the same plane, so they are try gone little plainer. And the question this next question wants us determined The relative bond angles associate ID with the, um, with each central adam. Um, just to make it easier as generalization. All of the atoms which have SP three hybridization and our tetra hydro are, um but they have bond angles of 100 and 9.5 degrees. Um, between their bonds in the atoms, which RSP to hybridized and our try Gondol plainer have bond angles of about 120 degrees. Um, next this question wants to know what is the most polar bond in Aspar team? Um, and before I answer this question, if I was useful to first circle which groups, we have an aspartame, um, to identify them. Um, so an aspirin Tehn. We have this one Esther group, which is polar. You also have this, um, this a my group, which is also polar. And we also have this a mean group which is also, um, slightly polar. And we also have a car boxful group, which is a polar. We also have our benzene languages, not polar. Um, but that is not relevant to the question being asked which is which is the most polar bond. So of the functional groups I have identified in general, the most polar of them is the car boxing group, and the most polar bond in the car boxful group is the carbon oxygen bond. Um, and this question is now asking if we predict aspartame to bi polar or non polar. So, as I have stated before, we have an Esther and a mydd and Amy and her car boxer group in aspartame. And all of these four functional groups are polar. Um, and this is compared to our one benzene ring in aspartame, which is non polar. So given that we have war poem, we have much more polar groups present in this compound. We would expect aspartame to bi polar. Um, next, the question is asking if, um, aspartame is expected to possess residents. Um, and resonance as a reminder, just describes the de localization of electrons, um, within a molecule. And if you look at the structure of, um, Aspartame without my drawings in the way, we can start to see where any residents might occur, and all residences exact occur where the pie orbital&#x27;s are overlapping in this molecule. And that will happen with the Ben zines with benzene ring. And with this car box, Oh, group. Um, So given this aspartame is expected to possess residents, um, at the benzene ring in the car box, it&#x27;ll group, um and this is due to overlapping, um, orbital&#x27;s specifically of the pie um pi r bittles that are overlapping within those two functional groups. Um, finally, your questions asking, um us to balance the equation for the combustion of aspartame. Um, and so we just have to write out what our reactions are, Um, and combustion. It&#x27;s always oxygen as the other reactant. And we know that this one is unusual as it produces, um, nitrogen dioxide. But it still has the other standard, um, products of combustion, which is carbon dioxide and water. So now we can begin to balance this equation. So, like with any other combustion equation, is useful to first balance the carbons and hide rins, and in this case, the night trillions before we start balancing the number of oxygen&#x27;s. So if we bounced a number of carbons, um, we need 14 on both sides. Similarly, we need 18 Hodgins on both sides. Um, and you need to measure Jin&#x27;s on both sides. So all that&#x27;s left now is to balance the number of oxygen atoms. Um, and we have a total loves. Um, let&#x27;s see, we have a total of for you one oxygen atoms on the right hand side. Um, so we need to bounce that on the left hand side, keeping in mind that there are five oxygen atoms present in Aspar team so that this means we only need to but, um, add 36 more oxygen atoms, and we can do that by making it 18 oxygen gas molecules reacting. And with this, this equations bounced. Next, the question wants us to calculate the weight of carbon dioxide that can be prepared from 1.68 grams of aspirin Team being mixed with 2.11 grams of oxygen guests. Um, so first, let&#x27;s just organize it on a small table What we need to know. So we are reacting 1.68 grams of Aspar team with, um, 2.11 grams of oxygen. Um, and you want to know how much carbon dioxide will be produced. So before we do this, let&#x27;s just calculate be molecular weights of each compound. And we are, you know, the molecular weight of ass pertained to be 294.34 grams per mole. We know the molecular weight of oxygen to be 32 grams per mole, and we can figure out the molecular weight apartment dioxide by, um summing the weight of carbon and to office and Adams, and that will have a total molecular weight of 44.1 grams per mole. Um, so first we want to determine, um, what is the limiting re agent? Um, and is part of this? Let&#x27;s first calculate the number of mole of Aspar team we have. Um and we find that by dividing how many Grimm&#x27;s? Oh, uh, copy the question wrong. It should be. Actually, 162 grams of Asper teen. Okay, So to find the number of alas, for Team, we just refer back to our conversion triangle here, which tells us that the number of mole can be found by dividing the mass of the compound by its molecular weight. So we will divide um ah 101.62 grams of Aspar team, with its molecular weight in find. The 1.60 grams of aspartame contains 5.5 times 10 to negative three Mol Ah, Vasbert team. And similarly, we need to find the number of mole of oxygen in our 2.11 grams. So we&#x27;ll do the same. Divide the weight of oxygen by its molecular weight in grams per mole, and we will find that we have um, 0.66 grams per mole. Um, And now, to determine what is limiting, we need to determine. Uh, hello, Money. Mole of oxygen is required to completely react with our 5.5 times. 10 to negative three. Mole of Aspar team. It could land grants move should just be 0.66 This is for oxygen. And this is for aspirin. Okay. So, deterrent. To determine how many moles of oxygen we need to react with our number of move Aspar team, we just need to do a quick story que metric calculation where we multiply the number of mole of aspartame we have by the ratio with which, um, Aspar team is consumed, um, versus the rate at which, um, oxygen gas is consumed. So for everyone will have ascertained consumed 18. Mole of oxygen is being consumed. So this means that number of mole of oxygen we need to react with our amount of Aspar team is 0.991 mole oxygen and you&#x27;ll notice that this value the amount of oxygen we need to react completely with our ass for team is less than the amount of oxygen we have. So that means that oxygen is the limiting re agent. So we have to use oxygen, um, as a jumping off point to calculate, um, how many mole of carbon dioxide is produced given that we can completely react? Um, only 0.6 mol of oxygen. And we can figure this out with another story geometric calculation by multiplying the number of mole of oxygen we have by the rate at which it is consumed, um, in the combustion of gas per team. So for every 18 full of oxygen consumed, 14 mole of carbon dioxide is being produced in the reaction. So that means that number of mull of oxygen being produced in the complete, um, combustion, um, of aspartame given that oxygen is limiting re agent is 0.0 eight for eight mole of carbon dioxide being produced. And the question wants us to report the amount of oxygen um being produced in grands. So we just have to do another mole to Graham conversion, which, if he reference our conversion triangle again, tells us that the mass in grams of a compound can be found from the product of its number rules and of its molecular weight. So we will multiply the number of mole of carbon dioxide we have by the molecular weight of carbon dioxide, which we calculated previously to be 44.1 grams per mole. And this tells us that, um, from this reaction, a total of 37.3 grams of carbon dioxide was produced.

Kevin Zaborsky · Answer

and this problem were given these three structures and were pulled that for each of these molecules, they&#x27;re either 01 or two pyro centers. All you have to do is go through and find where the Cairo centers are. If there are any in each one of these molecules and circle them. So remember that a Cairo center has to have a central carbon atom that is Singley bonded to four different groups. So we start with the structure on the far left. We notice that all of these carbon atoms contained double bonds and therefore none of them qualify as a Cairo center. So that first structure has zero Cairo center. So we don&#x27;t circle anything on it. Move on to the middle structure than and we see that all of these carbon atoms are bonded to two identical hydrogen atoms and therefore do not qualify to be a Cairo center. In this carbon, Adam has the same functional group attached to it on either side. So that also does not qualify to be a Cairo center. So in the 1st 2 structures, from left to right, neither one of them has any Cairo centres, so we don&#x27;t circle anything. Finally, with the structure on the far rate we know that are all the carbon atoms containing double bonds do not qualify as viral centers. So that&#x27;s all of these. And we also know that this carbon atom and this carbon Adam both do not qualify, either because they&#x27;re both onto the two identical hydrogen groups. So all that leaves is this carbon Adam and this carbon atom in those end of being the Cairo centers. Because if we look, we have one to three or different groups wanted to that carbon atom, and that makes it a Cairo center. And we also have one to re or different groups bonded to that carbon atoms. So that&#x27;s also a Cairo center. So we&#x27;ve identified the two Cairo centers that exist in that third molecule, and we&#x27;ve circled them and therefore completed the problem

Ronald Prasad · Answer

for part A. The two amino acids used to prepare Aspar team are Spartak acid, which has a structural formula. On the second. Amino acid is fennel Alan Een, which has the structural formula. Yeah, the two amino acids used to prepare Aspar team. And for part B, there is a concern that methanol may be produced from the decomposition of Aspar team. From what portion of molecule that can this be produced so methanol can be produced? Ah, by the following our group C 02 c H three plus water will produce are C 02 age plus the methanol which is here so methanol can be produced, um, through the hydraulic cysts of the federal Elhanan.

Problem

There are 25 $\mathrm{mg}$ of caffeine, $\mathrm{…

Problem 2 Easy Difficulty

What evidence shows that it would be dii cult to exceed the lethal dose of aspartame?

Answer

It is rpactically impossible for a person to consume such a high volume of diet soft drinks, and hence, it is rightly said that it would be difficult to exceed the lethal dose of aspartame.

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It is rpactically impossible for a person to consume such a high volume of diet soft drinks, and hence, it is rightly said that it would be difficult to exceed the lethal dose of aspartame.

Living by Chemistry

Theodore D.

Lizabeth T.

Stephen P.

Karli S.

Intro To Chem - Introduction

Classification and Properties of Matter

Angelica M. StacyLiving by Chemistry

Theodore D.

Lizabeth T.

Stephen P.

Karli S.

Angelica M. Stacy

Living by Chemistry