what-happens-to-the-magnitude-of-the-electric-force-between-two-opposite-charges-if-the-magnitude--2

Question

What happens to the magnitude of the electric force between two
opposite charges if the magnitude of each charge is halved and the
distance between their centers is halved?
(A) It is doubled.
(B) It is quadrupled.
(C) It is halved.
(D) It remains the same.

Salamat Ali · Accepted Answer

let me have a force between F force between the two charges. Q one. There&#x27;s a force constant Cute Que tu derided by our square. Now, if we have the magnitude of key one if I have this one and I have this one, Um And so this is a true story, um, derided by And then I have the the distance between them and take the square. What I get here is okay, Cuma, you too divided by four are square and from the squaring our dividing our by two Oh, the four goes up So it cancel out these floors and we see the force of man Sam. Bye. By changing the main street of each artist 0/2 And there decreasing the radius tow. Have we see The force remains the same. So Option D is the right answer

Ze-Han Lee · Answer

So in this problem we have two judges. You wanna que tu and they&#x27;re separations D. Okay, So based on the Quilmes law, we know that the force between them is over for pie. Absolute Q one Q two over D Square. All right, so in this problem, suppose we double Q one Q two and we Ah, half the separation d so d becomes half t. So let&#x27;s say the change of the magnitude of the force having this case equal for pie. Absolutely not. Two key one took you to Dubai by half off D squared. Right? So this gives you 16. Ah, so let&#x27;s say this is f f and F crime just to make them different. So there&#x27;s a quote 16 half. So as you can see that Ah ah, the force the magnitude of the force we&#x27;ll become 16. Increases affect her off

Abhishek Jana · Answer

so the force between two charges little Q and big Q is if e. Which is constant times little Q over bake you by r squared. No, If, um, the charges and the distance between the charges are doubled, then let&#x27;s see what happens to the force. So we have no two little Q times to make you over. Twice are. And then there&#x27;s a square. So this expression is nothing but the original force that we had there. So this is it will do the original force. So option ese. Great choice think.

Kayla Gephart · Answer

so at the top here we have two spheres of charge. Q on and Q two until the force between them is going to be. K times Q. One times keep to over R squared. Now at the bottom, The electric charge of each of these fears has tripled, so our new force is going to be K Times three Q, one times, three Q two over R squared and that can be simplified to equal nine times K types. Q. One chemist acute too over R squared and to the Final Fours after the charge has been tripled on both the spheres is nine times the original force.

Dading Chen · Answer

Okay, so the answer is nothing. OK, so that you have to feel remains constant is because we know you after a few e is equal to force divide in charge. So he only depends on the force and the location of the charge. Ok, so no matter how you change to the test charge, you want effects. You that review. Okay. And this is the answer for this question. Thank you.

Kayla Gephart · Answer

So here I have written out the original force F then for part A. We have the charge. A is doubled, and so the new force is K times two times the original. Q A. Times Q B times are squared. We can pull that two out in front, and then that&#x27;s just equal to two times F for B. We have Q and Q B are cut in half, and so we have. The force is equal to K times 1/2 Q A times, 1/2 Q B over R squared, and that&#x27;s equal to 1/4 times f for part C. We have ours tripled. And so the new force is K times. Cute, eh? Times Q B over three r squared and that&#x27;s gonna be 1/9 F. Then for part D, we have that are is cut in half. And so for the new force, we have K Times Q A Times Q B over 1/2 R squared, and that&#x27;s gonna give us four F. And then finally, for partney que a is tripled in our is doubled. And so for a new force, we have K Times three Q A times Q B over two R squared simple flying that we get 3/4 F

Problem

To make this paragraph most logical, sentence 5 …

Problem 41 Medium Difficulty

What happens to the magnitude of the electric force between two
opposite charges if the magnitude of each charge is halved and the
distance between their centers is halved?
(A) It is doubled.
(B) It is quadrupled.
(C) It is halved.
(D) It remains the same.

Answer

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