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What happens to the magnitude of the electric force between twoopposite charges if the magnitude of each charge is halved and thedistance between their centers is halved?(A) It is doubled.(B) It is quadrupled.(C) It is halved.(D) It remains the same.

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Chapter 4

Practice Test 4

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What happens to the electr…

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Charges $q$ and $Q$ attrac…

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Two charged objects are ve…

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What happens to the streng…

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Two charges, $q_{\mathrm{A…

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How does the distance betw…

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$\bullet$$\bullet$ Two une…

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A force, $F$, is measured …

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When you double the distan…

let me have a force between F force between the two charges. Q one. There's a force constant Cute Que tu derided by our square. Now, if we have the magnitude of key one if I have this one and I have this one, Um And so this is a true story, um, derided by And then I have the the distance between them and take the square. What I get here is okay, Cuma, you too divided by four are square and from the squaring our dividing our by two Oh, the four goes up So it cancel out these floors and we see the force of man Sam. Bye. By changing the main street of each artist 0/2 And there decreasing the radius tow. Have we see The force remains the same. So Option D is the right answer

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