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Hello everyone, this is problem 91 from chapter 18.
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It gives us in a figure a carnot cycle, and it tells us there are four processes in a carno cycle.
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So there's an isotherm, an adabat, another isotherm, and another adabat.
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So let me call these different points, a, b, c, and d.
00:28
So i've tried to draw it here.
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It's kind of rough.
00:31
C to d is supposed to be an isotherm, b, or a, or a, or a, to b to b to c is an a -dobat and d to a is an a -dabat.
00:40
And so it asks us to prove that the efficiency is 1 minus t -c over t -h, which is what we expect.
00:47
So beginning with what we know the definition of efficiency is, we can write this as w over qh or 1 minus qc over qh.
01:04
So really we just need the heat, the heat exhausted of the cold reservoir divided by the heat, taking in at the hot reservoir.
01:17
We know that the heat taking it at the hot reservoir is just going to be in a to b, and the heat exhausted at the cold reservoir is just going to be the heat exhausted along c to d.
01:28
This is because these other two processes, process 2 and process 4, are 80 bats, and so the heat exchange is 0.
01:37
So using the fact that processes 1 and 3 are isotherms, we see that the efficiency is 1 minus nr, nr t subc log of vc over vd, and then over nrth, log of vb over va.
02:18
Okay, and we'll notice that immediately the nrs cancel out.
02:25
And so now we need some way to relate vc and vd and vb and va...