Question
What is contained in array arr 1 after each of the following sets of statements are executed?
Step 1
int[] arr1 = new int[5]; After this statement, arr1 is an array of size 5 with all elements initialized to 0. Show more…
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Refer to the following code segment. You may assume that array arr 1 contains elements arr1 $[0], \operatorname{arr} 1[1], \ldots, \operatorname{arr} 1[\mathrm{N}-1],$ where $\mathrm{N}=\operatorname{arr} 1 .$ length. int count $=0$ for (int $i=0 ; \quad i < N ; \quad i++)$ if $(\operatorname{arr} 1[i] \quad !=0)$ { $\operatorname{arr} 1[\text { count }]=\operatorname{arr} 1[i]$ count++; 2 } int []$\text { arr } 2=\text { new int [count }]$ for (int $i=0 ; \text { i }< \text { count } ; \quad i++)$ $\operatorname{arr} 2[i]=\operatorname{arr} 1[i]$ If array arr 1 initially contains the elements 0,6,0,4,0,0,2 in this order, what will arr2 contain after execution of the code segment? (A) 6,4,2 (B) 0,0,0,0,6,4,2 (C) 6,4,2,4,0,0,2 (D) 0,6,0,4,0,0,2 (E) 6,4,2,0,0,0,0
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