We know that 238 grams of uranium contains Avogadro's number of atoms, which is $6.023 \times 10^{23}$. Therefore, 1 kg (or 1000 grams) of uranium will contain:
\[N = \frac{1000}{238} \times 6.023 \times 10^{23} = 2.53 \times 10^{24} \text{ atoms}\]
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