Question
What is the approximate time required for a hemoglobin molecule to diffuse through a cell membrane? Hint: The diffusion constant $D$ is approximately proportional to $1 / r$ where $r$ is the diameter of the diffusing particle or atom. Estimate the diffusion constant of a hemoglobin molecule from the value of $D$ for an oxygen molecule in Table 15.1
Step 1
The formula is given by $T = \frac{\Delta R^2}{D}$, where $T$ is the time required for diffusion, $\Delta R$ is the distance or thickness of the cell membrane, and $D$ is the diffusion constant. Show more…
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The average time it takes for a molecule to diffuse a distance of $x \mathrm{cm}$ is given by $t=\frac{x^{2}}{2 D}$ where $t$ is the time in seconds and $D$ is the diffusion coefficient. Given that the diffusion coefficient of glucose is $5.7 \times 10^{-7} \mathrm{cm}^{2} / \mathrm{s},$ calculate the time it would take for a glucose molecule to diffuse $10 \mu \mathrm{m},$ which is roughly the size of a cell.
The average time it takes for a molecule to diffuse a distance of $x \mathrm{cm}$ is given by $$ t=\frac{x^{2}}{2 D} $$ where $t$ is the time in seconds and $D$ is the diffusion coefficient. Given that the diffusion coefficient of glucose is $5.7 \times 10^{-7} \mathrm{cm}^{2} / \mathrm{s},$ calculate the time it would take for a glucose molecule to diffuse $10 \mu \mathrm{m},$ which is roughly the size of a cell.
The average time it takes for a molecule to diffuse a distance of x cm is given by t = (x^2) / (2D), where t is the time in seconds and D is the diffusion coefficient. Assume that the diffusion coefficient of glucose is 5.70 × 10^(-7) cm^2/s. Calculate the time it would take for a glucose molecule to diffuse 11.5 μm.
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