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What is the approximate value of the equilibrium constant $K_{P}$ for the change$\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}(l) \rightleftharpoons \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}(g)$ at $25^{\circ} \mathrm{C}$ . (Vapor pressure was described in the previous chapter on liquidsand solids; refer back to this chapter to find the relevant information needed this problem.)

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Chemistry 102

Chapter 13

Fundamental Equilibrium Concepts

Chemical Equilibrium

Aqueous Equilibria

Carleton College

Drexel University

University of Maryland - University College

Lectures

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A liquid is a nearly incom…

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A liquid is a state of mat…

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If the value of the equili…

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What is the value of the e…

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Consider the reaction.…

01:39

The vapor pressure of wate…

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For the reaction $\mathrm{…

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At a temperature of $60^{\…

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Relationship of $K_{c}$ an…

03:27

Calculate $\Delta_{r} G^{\…

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How is the value of the eq…

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Using Equilibrium Constant…

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At $1045 \mathrm{K}$ the p…

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An equilibrium mixture at …

04:50

The equilibrium constant $…

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this question says, What is the approximate value of the equilibrium? Constant K. P. For the change c two h 50 C. Two h five liquid going to the same thing in the gas form at 25 degrees Celsius. They give us this little note says Vapor. Pressure was described in a previous chapter on liquids and solids. Refer back to this tractor to find a relevant information needed to solve this problem. I couldn't find what it was referring to that chapter. But what we do need to know is the vapor pressure of this compound di ethyl ether at 25 degrees Celsius. And it tells us, if you look up in a chart that's 250.7 atmospheres. So the way you find KP normal problem, it's the partial pressure from the gases in the products over the reactant. Since there's none in the reactors, we just use the partial pressure of the gas and the products. You don't square anything because there's no turn proceeding either of these. So the partial pressure well of diet, or either at 25 degrees is K piece O K. P equals 0.7, according to this number found online

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