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What is the best coefficient of performance possible for a hypothetical refrigerator that could make liquid nitrogen at $-200^{\circ} \mathrm{C}$ and has heat transfer to the environment at $35.0^{\circ} \mathrm{C} ?$

$C O P_{\text {ref }}=0.311$

Physics 101 Mechanics

Chapter 15

Thermodynamics

Thermal Properties of Matter

The First Law of Thermodynamics

The Second Law of Thermodynamics

Rutgers, The State University of New Jersey

University of Washington

Hope College

University of Winnipeg

Lectures

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01:00

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01:10

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01:04

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coefficient off performance for refrigerator is given by coefficient of performance for heat and you minus one on DDE. We know that coefficient of performance for heat engine is given us you supplied, divided by the work done. So Walden is eight times the huge supplied, so this is equal to wonder about it by efficiency. So let's find the car knows efficiency. We know cardinals efficiency is given by which is maximum efficiency one minus t c divided by th. So let's substitute on the values we have. So, temperature Oh, cold reservoir is negative 200 degrees Celsius. So in terms of Kelvin, that would be 73. Kelvin, all you have to do is to add to 73 to the two negative 200 on dhe heart preserver that his environmental temperature is 35 degrees Celsius, so that will be 308 kelvin. So if you do this calculation, you will find the answer is 0.76 see, So C O HP, in this case is one divided by 0.76 Think this is equal to 1.311 so C o coefficient off performance for refrigerator is this minus one? So 1.311 minus one. This is a call to 0.311 Thank you.

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