00:01
Chemistry and so here we have two things that we should be defining when we are considering a solution so firstly we have the solvent so this is the major component and secondly we have the solute which is the minor component and we may have one or more solute per solvent so we're investigating colligative properties still so these are the properties and the mixtures of solutions that depend upon the concentration of the solute molecules and ions and so for example we've got the freezing point of or the boiling point elevation.
00:32
So the formula for the boiling point elevation is as follows.
00:37
Delta t .b, that's equal to i, kb, c, m.
00:45
Where i is the number of ions.
00:47
Kb is the constant value, and cm is the molarity.
00:54
So we can calculate the moles of 0 .133 grams of glycerol.
01:00
So nb is equal to 0 .133 grams.
01:05
We divide that by 92 .1 grams per mole to get 0 .0 .0144 moles.
01:15
So the amount of water we have is 20 grams.
01:18
And so the molarity of the solution we can calculate is cm.
01:25
So that is the moles that we calculated, 0 .0 .0144.
01:30
Divided by the mass of the solvent that is in units of kilograms...