Question
What is the centripetal acceleration of the Moon? The period of the Moon's orbit about the Earth is 27.3 days, measured with respect to the fixed stars. The radius of the Moon's orbit is $R_{M}=3.85 \cdot 10^{8} \mathrm{~m}$.
Step 1
First, we need to convert the period of the Moon's orbit from days to seconds. There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. So, the period in seconds is: T = 27.3 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute ≈ Show more…
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What is the centripetal acceleration of the Moon? The period of the Moon's orbit about the Earth is 27.3 days, measured with respect to the fixed stars. The radius of the Moon's orbit is $R_{M}=3.85 \cdot 10^{8} \mathrm{~m}$
The Moon revolves around Earth in a circular orbit with a radius of 3.84x10^8 m. It takes 27.3 days for the Moon to complete one orbit around Earth. What is the centripetal acceleration of the Moon?
Find the centripetal acceleration of the moon toward the earth, assuming that the orbit of the moon is a circle of neclius 239,000 miles $=3.85 \cdot 10^{8} \mathrm{m},$ and the time for one complete revolution is 27.3 days $=2.36 \cdot 10^{6} \mathrm{sec}$
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